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OpenStudy (anonymous):
what angle between two vectors would give the maximum cross product?
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OpenStudy (anonymous):
By maximum cross product, you mean the maximum magnitude of a cross product?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
it should be 90 degrees
OpenStudy (across):
\[|\vec{A}\times \vec{B}|=|\vec{A}||\vec{B}|\sin\theta.\]You be the judge.
OpenStudy (anonymous):
it should be 90 degrees
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OpenStudy (anonymous):
that's a dot product. I need the cross product
OpenStudy (across):
That's not a dot product.
OpenStudy (anonymous):
yeah :))
OpenStudy (anonymous):
how does that give a vector?
OpenStudy (across):
I'm taking its magnitude...
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OpenStudy (anonymous):
but the magnitude of the cross product changes with the direction as well as the magnitude, no?
OpenStudy (across):
The direction of a vector does not affect its magnitude.
OpenStudy (anonymous):
oh. thanks i thought it did
OpenStudy (across):
A pencil will have the same length regardless of where you point with it.
OpenStudy (anonymous):
|A⃗ ×B⃗ |=|A⃗ ||B⃗ |sinθ
now we know that the maximum value of sin theta is 1 and that will only happen if theta is equal to 90 degrees.
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OpenStudy (across):
Or a multiple thereof.
OpenStudy (anonymous):
yep
OpenStudy (anonymous):
ok thank you both
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