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Mathematics 15 Online
OpenStudy (anonymous):

what angle between two vectors would give the maximum cross product?

OpenStudy (anonymous):

By maximum cross product, you mean the maximum magnitude of a cross product?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

it should be 90 degrees

OpenStudy (across):

\[|\vec{A}\times \vec{B}|=|\vec{A}||\vec{B}|\sin\theta.\]You be the judge.

OpenStudy (anonymous):

it should be 90 degrees

OpenStudy (anonymous):

that's a dot product. I need the cross product

OpenStudy (across):

That's not a dot product.

OpenStudy (anonymous):

yeah :))

OpenStudy (anonymous):

how does that give a vector?

OpenStudy (across):

I'm taking its magnitude...

OpenStudy (anonymous):

but the magnitude of the cross product changes with the direction as well as the magnitude, no?

OpenStudy (across):

The direction of a vector does not affect its magnitude.

OpenStudy (anonymous):

oh. thanks i thought it did

OpenStudy (across):

A pencil will have the same length regardless of where you point with it.

OpenStudy (anonymous):

|A⃗ ×B⃗ |=|A⃗ ||B⃗ |sinθ now we know that the maximum value of sin theta is 1 and that will only happen if theta is equal to 90 degrees.

OpenStudy (across):

Or a multiple thereof.

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

ok thank you both

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