One more! The denominator of a fraction is 1 more than the numerator. If the numerator is decreased by 1, the value of the resulting fraction is 3/4. What is the original fraction?
Let the fraction be x/y.Now here given that y=x+1 and also (x-1)/y=3/4.So there you go two equations.Now solving
Pavan has given you the two equations Let me write it down again Let the fraction be \( \frac{x}{y}\) Denominator y= x+1 If the numerator is decreased by 1, the value of the resulting fraction is 3/4. \[\frac{(x-1)}{y}= \frac{3}{4}\]
\[y=x+1 \tag{1}\]\[\frac{x-1}{y}= \frac{3}{4}\tag{2}\] Can ypu simplify the second equation ?
Hmmmmm maybe get rid of the fraction on the left, so it looks like this? x-1=3/4y? (not 4y but 3/4 times y?)
Yes, But just try to cross multiply ,it'll look simpler :)
If we xmultiply, isn't it 4(x-1)=3y?
Oh then plug in y=x+1 SOLVING!
Fraction: 7/8 Diyadiya thank you so much!
Glad to Help :D
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