I have a probability question: What is the probability that a car containing 7 people chosen out of 12 (4 boys, 8 girls) has Peter and Manuel in it (both are boys)?
doesn't look like "boys and girls" matter for this question, just "pick 7 out of 12, what is the probability that peter and manuel are picked?
i don't know you tell me
ok , it doesn't matter that they are boys, just that they are chosen
your denominator will be \[\dbinom{12}{7}\] the total number of ways you can choose 7 out of 12 numerator will be \[\dbinom{2}{2}\times \dbinom{10}{5}\] that is the number of way you can pick the two out of two (which is clearly only one way) times the number of ways you can pick the remaining 5 out of the remaining 10
so in fact you have \[\frac{\dbinom{10}{5}}{\dbinom{12}{7}}\]
Yes that's what I got! I did it the satellite way before satellite explained it to me!!!
You remember how you would always have to do things for me twice, once your way and once my way? Well my math class is getting into probability and now I am learning your way and I must say it is much easier
yes i think it is good work
thanks
Join our real-time social learning platform and learn together with your friends!