Question

Factor the GCF and then the resulting trinomial: 3x3 - 3x2 - 6x


x(3x - 6)(x + 1)


3(x - 2)(x + 1)


3x(x - 2)(x + 1)


prime

Answer 1

3(x - 2)(x + 1)

Answer 2

3x3 - 3x2 - 6x
= 3x(x^2-x-2)
= 3x(x-2)(x+1)
can you choose the answer yourself?

Answer 3

@Callisto you should match with th formulas

Answer 4

@Rohangrr can you explain what formula please?

Answer 5

@Callisto dude dont take to ur heart
i just reminded u the post was mistakenly putted by my bro in my absence

Answer 6

Hmm.. i'm not a guy, so i'm not a dude? and sorry that doesn't sound like 'reminding' me. Anyway, does the asker know how to do it?

Answer 7

No, then again the comments here are highly entertaining to be honest.

Answer 8

lol, first take out the common factor...
you can see that in 3x3 - 3x2 - 6x
x is the common factor (as there is an x in each term ) 3 is another common factor (as the coefficients are multiple of 3), understand this part?

Answer 9

Kind of, the whole factoring part doesn't make sense to me period.

Answer 10

just do it step by step then :)

Answer 11

So, next, take out 3x as the common factor in 3x3 - 3x2 - 6x
you'll get 3x(x^2-x-2), understand this part?

Answer 12

3x^3-3x^2- 6x
In all the three terms x is common and 3 is also common
so, we can take 3x outside and re-write as 3x(x^2-x-2)
(x^2-x-2) can factorise as (x-2)(x+1)
so we can factorise as 3x(x-2)(x+1)
here, GCF= 3x
trinomial can factorise as 3x(x-2)(X+1)