at http://tutorial.math.lamar.edu/Classes/DE/Linear.aspx in example 1, the p(t)=0.196 why not is it p(t)=0.196v, where has the v gone?
because the form is\[y'+p(t)y=q(t)\]here it is \(v\) instead of \(y\)\[v'+p(t)v=q(t)\]so the bit next to the v is p(t)=0.196
didn't get that :(
whatever function is multiplying by the variable you are trying to solve for is p(t)
here you are solving for v hence p(t) is the thing multiplied by v in the equation
okkk got it
thankssssssssssssssssssssssssssssss a tonne bro
no problemoo!
@TuringTest what is this new functionality of this website? on my question it is giving me two options bump or close, what does it mean?
as my question is now solved so should I close it?
you can only have one active question at a time that way people don't post 5 at once yes, close it, you can still find it by hitting "closed question" it's just not on the main board anymore
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