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use the rational root theorem and the factor theorem to help solve the following equation X^4-4x^3+14x^2-19x+28=0 A) (-10, -1, 0, 1/4) B) (-10, -1, 0, 4) C) (+-10, -1, 4) D) no rational solution
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no rational solution
Try 0 (because it is in choice A and B, and it's easy to evaluate) 28≠0 so A and B are out.
C has a -1. That isn't too hard 1+4+14+19+28 that isn't 0 so we are left with D
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