Question

standard form of (-1,-7)(1,-1)??

Answer 1

First find the slope

m = (y2-y1)/(x2-x1)


m = (-1-(-7))/(1-(-1))


m = (-1+7)/(1+1)


m = 6/2


m = 3


So the slope of the line that passes through the two points is 3


Now use the slope along with the first point to find the equtaion of the line in slope intercept form


y = mx+b


-7 = (3)(-1)+b


-7 = -3+b


-7+3 = b


-4 = b


b = -4


So the equation of the line in slope intercept form is y = 3x-4


Now convert to standard form


y = 3x-4


-3x + y = -4


3x - y = 4