Find the equation of the line that contains the given point and has the given slope. Let y be the dependent variable and let x be the independent variable.
Point (4, 5), m = 2/3

this is what I figured but is not right...

y-5=2/3(x-4)
y=2/3x-8/3
y=2/3x-(8/3+5)
y=2/3x ?

Question

Find the equation of the line that contains the given point and has the given slope. Let y be the dependent variable and let x be the independent variable.
Point (4, 5),   m =	2/3


this is what I figured but is not right...

y-5=2/3(x-4)
y=2/3x-8/3
y=2/3x-(8/3+5)
y=2/3x ?

anonymous · Answer

y=2/3x-(8/3+5)

anonymous · Answer

I did do that but it is saying its wrong so I didnt know if i was doing something wrong

anonymous · Answer

do I need to reduce something

anonymous · Answer

y=2/3x-8/3 this must n=be the ans

callisto · Answer

y-5=2/3(x-4)
y=2/3x-8/3 <- Wrong for this step...

y-5=2/3(x-4)
y-5 = (2/3)x - (2/3)(4)
y-5 = (2/3)x - 8/3

Now, add 5 to both sides, can you work out the answer?

anonymous · Answer

well its 7 2/3 right?....23/3

callisto · Answer

Hmm.. you've 'accidentally' missed the -5 on the left hand side for your second step..

callisto · Answer

Yup, for the constant term only

anonymous · Answer

oh ok so with the neg it being +7/3 now for the ending

callisto · Answer

+7/3 ?

anonymous · Answer

y=2/3x+7/3

anonymous · Answer

which my assignment is now saying is correct

callisto · Answer

oop...my mistakes.. yea...you're correct!!

anonymous · Answer

ok thank you for your help

callisto · Answer

you're welcome