If the roots of $ax^2+bx+c=0$ are in the ratio m:n then
A.$mna^2=(m+n)c^2$
B.$mnb^2=(m+n)ac$
C.$mnb^2=(m+n)^2ac$
D.None of these

Question

If the roots of $ax^2+bx+c=0$ are in the ratio m:n then 
A.$mna^2=(m+n)c^2$
B.$mnb^2=(m+n)ac$
C.$mnb^2=(m+n)^2ac$
D.None of these

diyadiya · Answer

Let α and β be the roots 
$$\frac{α}{β}= \frac{m}{n}$$

anonymous · Answer

$$n \alpha = \beta m$$$$\alpha  +\beta = \frac{-b}a$$$$\alpha \beta = \frac c a $$Use these.

anonymous · Answer

Substitute the values of the roots using the ratio relation, just do it. I don't wanna type it out all out, it's too algebraic to type.

diyadiya · Answer

Wait i didn't get that ..

diyadiya · Answer

what's the value of the roots here?

callisto · Answer

It's very messy :(
Only things on the left are related to this question...

callisto · Answer

And for the second last step.. i should cross out the power of n, that is 2, instead of n, sorry :S

diyadiya · Answer

can you type the first equation ? :S

callisto · Answer

the first equation?

diyadiya · Answer

yeah i cant understand from the pic u attached

anonymous · Answer

lol, 'This sheet must not be taken away"

callisto · Answer

Sorry... Dunno if it makes better or worse

diyadiya · Answer

WOw Thank you Soo much!!!

callisto · Answer

Do you understand ?

diyadiya · Answer

Yup :)

callisto · Answer

Glad to help :D