Question

how do i find the fourth roots of 256? I have an idea of how to do it but im confused with how to start

Answer 1

You're looking for a number "x" such that when raise it to the fourth power, you get 256.

x^4 = 256
x*x*x*x = 256

Fortunately, you can find this by just starting to take small numbers to the fourth power. :)

1^4 = 1
2^4 = 2*2*2*2 = 16
3^4 = 3*3*3*3 = 81
4^4 = ... etc

Hope this helps. :)

Answer 2

I think you should find the sqroot 256 and then sqroot of the sqroot256

Answer 3

@PutuDani presents a very quick solution.

Answer 4

u could prime factorize 256 and then that no. out which appears 4 times in the factorizations . since 256 = 2^8 u are going to take 2 out 2 times.
so 2*2 = 4.