Happy sunday guys I need your help...taking a final test here is the quest...
x/2-y/3=5/6
x/5-y/4=43/10
solve by substitution.....hugs

Question

Happy sunday guys I need your help...taking a final test here is the quest...
x/2-y/3=5/6
x/5-y/4=43/10
solve by substitution.....hugs

anonymous · Answer

I don't understand the substitution part. Do you mean simultaneous equations?

anonymous · Answer

yes i do hate it you isolate the y like I can solve one half but when i pkug in the second variable it does not match
so 2x-3y=5

anonymous · Answer

-3y=5-2x
y=-5/3+2/3x

anonymous · Answer

plug it intothe second equation and I get all kind of bizarre answers

anonymous · Answer

You can re-write the equations as 
2x-3y=30
5x-4y=4300
This is simply just flipping the denominator so it multiplies with the numerator. Can you solve it now?

anonymous · Answer

I think so thanks for the idea:)

anonymous · Answer

Anymore problems just let me know :)

anonymous · Answer

:)