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Which is the extraneous solution of (pic about to be posted)? –5 –3 3 5
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square both sides
ok
-x = √ (2x + 15) (-x)^2 = ( √ (2x + 15) ) ^2 x^2 = 2x + 15 x^2 - 2x - 15 = 0 (x - 5) ( x + 3) = 0 Zero Product Property x = 5 or x = -3 5 is the extraneous root because if 5 is substituted into the original equation: -5 = √ (2(-5) + 15) Immediately, you see that the square root cannot equal a negative number. These "extra" roots that are not true solutions of the original radical equation are called extraneous roots and are rejected as answers.
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