Question

x^2 - 9 factored?

Answer 1

Hint:

a^2 - b^2 = (a+b)(a-b)

Answer 2

thanks

Answer 3

What's your answer?

Answer 4

(x-3 ) ( x+ 3 ) ?

Answer 5

gj

Answer 6

:)

Answer 7

x² + 9 (Not factorable under the reals, however it is factorable under the complex numbers)

(x - 3i)(x + 3i), where i = √(-1)


x² - 4

(x - 2)(x + 2)


x² - 1

(x - 1)(x + 1)


Edit: Mathteachr should be careful. She mentions that #1 is prime (cannot be factored).

Instead she should say can't be factored under the REAL numbers. In fact every quadratic can be factored. You have to mention the numbers you are working with.

This drives me crazy, it's no wonder that the math education in this country is declining.