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Mathematics 24 Online
OpenStudy (anonymous):

Find the limit of it exists lim x-> (x^3)ln(x)

OpenStudy (anonymous):

As x goes to what?

OpenStudy (anonymous):

a) 0 b)1 c) 2 d) 3 e) -INF

OpenStudy (anonymous):

x->0+ sorry

OpenStudy (anonymous):

yes, but you can break the problem up into 2 separate limits. \[\lim_{x \rightarrow 0+}x^3 * \lim_{x \rightarrow 0+}\ln(x)=0*-\infty\], so no matter the limit of ln(x), x^3lnx approaches 0 as x->0+

OpenStudy (anonymous):

it never reaches zero as we get infinitely closer to x=0 from the right (although x^3lnx=0 when x=1, but irrelevant), but the limit is still 0 from the right.

OpenStudy (anonymous):

Wasn't thinking, yes you are correct.

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