give the domain for the function f (x) = y-3 ____ y+5y-6
all real except -6 and 1
wait is the y on the bottom supposed to be squared?
no, just y
so it's \[y+5y-6\]
yes
in other words it's 6y -6
if you pull out the 6 you'll get 6(y-1)
the domain is defined a all real number except when the domain = 0 as it would be undefined
so it's undefined when y = 1
\[[\infty,1)\cup(1,\infty]\]
ohh, thank you!
your book probably has a D in front of what my answer is above for Domain
yash check it , it's been about a year since i've taken a math class lol
hey its f(x)=something variable in y so is it true??? i'm having a doubt..:\
that's true idk why it's like that
maybe she mean't f(y)
yeah thats what i'm trying to say
It says in the equation f(x)
or her teacher wasn't thinking when he gave her the question
:P yeah...lolzzz..:p
i think that's the answer the teacher wants otherwise the domain could be anything i think ll
yeah u r right hey @outkast please help me with my question too please
so if you add y+5y-6 then it would be undefined? i'm so lost :-/
no,we were not talking about that actually u wrote f(x)= something variable in y so acc. to that answer can be anything and if it is f(y)= variable fxn in y then his answer is correct..:)
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