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Mathematics 19 Online
OpenStudy (anonymous):

give the domain for the function f (x) = y-3 ____ y+5y-6

OpenStudy (anonymous):

all real except -6 and 1

OpenStudy (anonymous):

wait is the y on the bottom supposed to be squared?

OpenStudy (anonymous):

no, just y

OpenStudy (anonymous):

so it's \[y+5y-6\]

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

in other words it's 6y -6

OpenStudy (anonymous):

if you pull out the 6 you'll get 6(y-1)

OpenStudy (anonymous):

the domain is defined a all real number except when the domain = 0 as it would be undefined

OpenStudy (anonymous):

so it's undefined when y = 1

OpenStudy (anonymous):

\[[\infty,1)\cup(1,\infty]\]

OpenStudy (anonymous):

ohh, thank you!

OpenStudy (anonymous):

your book probably has a D in front of what my answer is above for Domain

OpenStudy (anonymous):

yash check it , it's been about a year since i've taken a math class lol

OpenStudy (anonymous):

hey its f(x)=something variable in y so is it true??? i'm having a doubt..:\

OpenStudy (anonymous):

that's true idk why it's like that

OpenStudy (anonymous):

maybe she mean't f(y)

OpenStudy (anonymous):

yeah thats what i'm trying to say

OpenStudy (anonymous):

It says in the equation f(x)

OpenStudy (anonymous):

or her teacher wasn't thinking when he gave her the question

OpenStudy (anonymous):

:P yeah...lolzzz..:p

OpenStudy (anonymous):

i think that's the answer the teacher wants otherwise the domain could be anything i think ll

OpenStudy (anonymous):

yeah u r right hey @outkast please help me with my question too please

OpenStudy (anonymous):

so if you add y+5y-6 then it would be undefined? i'm so lost :-/

OpenStudy (anonymous):

no,we were not talking about that actually u wrote f(x)= something variable in y so acc. to that answer can be anything and if it is f(y)= variable fxn in y then his answer is correct..:)

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