Find the probability that a 4-person team consists of 2 girls and 2 boys if the team is chosen at random from: a.3 girls; 3 boys b. 5 girls; 2 boys c. 2 girls; 6 boys d. 3 girls; 1 boy
Did you try making a tree for each?
The last one is impossible do you know why?
You only have 1 boy to choose from and you are suppose to get two boys out of that
I know the last one, but is there an algebraic way to do this?
i will show you how to do the first one i'm gonna make a tree
I know how to make a tree diagram but is the algebraic way to do it: (for example A) 3C2x3C2?
lol ok i don't like the tree way i was going to show you how to compare but nevermind... so the algebra way... And don't forget we are looking for probability k? one sec....brb
and yes we will need to use 3C2 * 3C2 since we have 3 boys and we are choosing 2 of them and since we have 3 girls and we are choosing 2 of them
But this only gives us the number of ways 2 boys and 2 girls can be chosen from 3 boys and 3 girls
now we have 3 boys and 3 girls right? That means we have 6 people to choose from?
But we are only selecting 4 right?
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