Find the probability that a 4-person team consists of 2 girls and 2 boys if the team is chosen at random from: a.3 girls; 3 boys b. 5 girls; 2 boys c. 2 girls; 6 boys
I'm not good with probability. :o
Ok, so we are looking for the probability of either getting just 2 boys, or just 2 girls.
for c, that's (2/8)*(1/7)*(1)*(1)*(4C2)
No, we can reduce the problem into finding the probability of EXACTLY 2 boys or EXACTLY 2 girls given 4 people. that makes it easier.
For b, (2/7)(1/6)*(1)*(1)*(4C2)
where are you getting these numbers?
for a, (3/6)(2/5)(3/4)(2/4)*(4C2)
well, essentially, for C, we calculate the probability of getting 2 girls then 2 boys, and then multiply it be 4C2 because order doesn't matter.
Same for B and A.
It's hard to explain, but even though the number decreases by one time, no matter what order you select the boys and girls from, you would still get the same probability. Thus we simply multiply that probability by the number of combinations that are possible.
a. 3/10 = .3
Alright, who is right? -_-
I thought you are the one just learned this technique from "Miama.."
I'm correct, because, LOL.
But ink man got a different answers than her.
Besides, Chloroplast didn't show his work. I always hated biology.
/her, if you're a girl
miama got 9/15 for the answer.
I believe you should trust her knowlege :)
So, that's settle down which method, right!
well, is this a test, or homework?
and 9/15 for which question?
she got 9/15 for a and this is a homework.
shall I write a python program and determine the answer for sure?
Can you bump this? I think other's could help more than me
and, I think Miama is right, but I will write a computer program to make sure.
Her user name is "myininaya"!
@inkyvoyd, I don't think that you're bad at bio :P Otherwise, how come you know where cholorphyll come from :)
@Perl this type of question pretty much like your!
I'm prtty bad at biology. It's my lowest grade out of everyhing else.
Actually, I forgot how to write programs in python, lemme search if I sitll have my old programs.
I don't have my calculator here, but according to Myininaya: a) 3C2 * 3C2 / 6C4 b) 5C2 * 2C2/ 7C4 c) 2C2 * 6C2/ 8C4
Well, She's most likely correct.
a) 3 * 3 / 3 * 5 = 3/5
Just plug them in the calculator to double check your manual work!
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