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OpenStudy (anonymous):
given that x^2y +y^2 = 5 determine dy/dx
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OpenStudy (anonymous):
the y is not in the exponent
OpenStudy (nottim):
so...just solve for x and y? or am i lookin at this wrong?
OpenStudy (anonymous):
idk
OpenStudy (nottim):
well...maybe just do algebra and rearrange to somewhat solve for x and y then... @Callisto ?
OpenStudy (anonymous):
@satellite73 @Callisto @dpaInc
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OpenStudy (anonymous):
\[x^2y +y^2 = 5\] \[2xy+x^2y'+2yy'=0\] now algebra to solve for \(y'\)
OpenStudy (anonymous):
#facepalm #brainfart
OpenStudy (callisto):
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