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Let \( S_n\) denotes the sum of first n terms of an AP. If \(S_{2n}= 3S_n\) then the ratio is equal to :
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\[\frac{\S_{2n}}{\S_n} = \frac{2n/2(2a+(2n-1)d}{n/2(2a+(n-1)d}\]
Answer is 6
oh wait
Ratio of \[\S_{3n}:\S_n\]
Its \(S\)
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3 it's given
Ok i guess there is something Wrong in the question the questions is Let \(S_n\) denotes the sum of first n terms of an AP. If \(S_{2n}=3S_n\) then the ratio is equal to : But in the hint they are finding the ratio of \(S_{3n} : S_n\)
It is an assumption that S2n:Sn = 3, i think it is asking to find other parameter
Okay i'll try to figure out the question lol :D Thanks anyways
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