Mathematics
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OpenStudy (anonymous):
Solve.
2x^1/3-2=0
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OpenStudy (anonymous):
Igot x=4. But I don't feel that is correct
OpenStudy (lgbasallote):
this is 2x^(1/3) - 2 = 0 yes?
OpenStudy (anonymous):
Yes
OpenStudy (lgbasallote):
hmm i'll guide you step by step...add two to both sides
OpenStudy (anonymous):
2x^1/3=2
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OpenStudy (lgbasallote):
good! now divide both sides by 2
OpenStudy (anonymous):
X^1/3=1
OpenStudy (lgbasallote):
now take the cube root of both sides...
OpenStudy (anonymous):
What exactly doz you mean
OpenStudy (lgbasallote):
oh wait..i meant cube both sides...you want x..so 1/3 has to cancel out..
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OpenStudy (anonymous):
So it would just equal. 1
OpenStudy (lgbasallote):
yes! :DDD
OpenStudy (anonymous):
Thankkk youu :)
OpenStudy (anonymous):
How about this next problem.. I reallly don't think I got it correct either..
(2x+1)^1/3=1
I got x=0
OpenStudy (lgbasallote):
get the cube root...then transpose the constant...then divide the constant..you'll get it if you do it step by step ;D
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OpenStudy (anonymous):
Lol Si does that mean I got that one wrong to?
OpenStudy (lgbasallote):
yeahhh =)))
OpenStudy (anonymous):
Ughhhh
OpenStudy (lgbasallote):
so...got it yet? /:) hehe
OpenStudy (anonymous):
Nooo
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OpenStudy (lgbasallote):
ok..cube both sides..ill guide you
OpenStudy (anonymous):
I'm beyond confused noww lol...
OpenStudy (lgbasallote):
you have (2x-1)^1/3 = 1 yes? your goal is to get the x on one side only..so you take away the exponent..how? by cubing it :DD now cube
OpenStudy (anonymous):
Sooo 8x^3+1=1
OpenStudy (lgbasallote):
no no.. when you cube it..the 1/3 gets canceled.
2x-1 = 1
get it?
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OpenStudy (anonymous):
yes. then you divide 2?
OpenStudy (anonymous):
the it will still equal 0
OpenStudy (lgbasallote):
oh no..2x - 1 = 1
2x = 1 + 1
OpenStudy (lgbasallote):
oh wait...it's positive??? im sorry you were right
OpenStudy (anonymous):
Ahhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh! :D that makes me happy. hahah Thanks for your help! I actually understand :D
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OpenStudy (lgbasallote):
<tips hat>
OpenStudy (anonymous):
Like a mathematical genius. (: