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Mathematics 18 Online
OpenStudy (anonymous):

Solve: sin3Ө = 0

OpenStudy (anonymous):

arcsin

OpenStudy (anonymous):

sin3Ө = sin 0

OpenStudy (anonymous):

--> Ө = 0

OpenStudy (anonymous):

i don't get it -.-

OpenStudy (anonymous):

Sin 0 =0. 0*any number is 0, so theta would be 0 because 0*3=0

OpenStudy (anonymous):

Ok?

OpenStudy (anonymous):

0 is not the only solution

OpenStudy (anonymous):

Really?

OpenStudy (anonymous):

sin(180º)=0...right? sin(360º)=0, sin(-180º)=0

OpenStudy (anonymous):

Okk then ?

OpenStudy (anonymous):

you have to account for every angle

OpenStudy (anonymous):

what is 120 degrees k mean ?

OpenStudy (anonymous):

what is "k" anyway ?

OpenStudy (anonymous):

k is an integer, any integer

OpenStudy (anonymous):

which is how you account for every possible angle theta can be

OpenStudy (anonymous):

how did they get 120 degrees k then ?

OpenStudy (anonymous):

the answer to this is theta=k*60º, where k is any integer

OpenStudy (anonymous):

for example k=1 sin(3*60)=sin(180)=0 k=0 sin(3*0)=sin(0)=0 k=-1 sin(3*-60)=0 k=2 sin(3*2*60)=sin(360)=0

OpenStudy (anonymous):

ohh

OpenStudy (anonymous):

where did you get the 60 from?

OpenStudy (anonymous):

well you could also write 0+k*60º, since we established that the reference angle was 0, but the 0 is unnecessary

OpenStudy (anonymous):

so k= either 0,1,2,3 ?

OpenStudy (anonymous):

k is ANY integer

OpenStudy (anonymous):

the equation will be true whatever the value you plug in for k is

OpenStudy (anonymous):

i see

OpenStudy (anonymous):

suppose k=500 type in your calculator sin(3*500*60º) you end up with 0

OpenStudy (anonymous):

ahh ok

OpenStudy (anonymous):

Sin and cos have periodic of 2 pi => sin 3Ө = sin 0 + k 2pi => 3Ө = 0 + k 2pi => Ө = k 2pi / 3 = k 60 degree k = 1, Ө = 60 k = 2, Ө = 120 ... so on

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