Mathematics
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OpenStudy (anonymous):
Solve: sin3Ө = 0
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OpenStudy (anonymous):
arcsin
OpenStudy (anonymous):
sin3Ө = sin 0
OpenStudy (anonymous):
--> Ө = 0
OpenStudy (anonymous):
i don't get it -.-
OpenStudy (anonymous):
Sin 0 =0. 0*any number is 0, so theta would be 0 because 0*3=0
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OpenStudy (anonymous):
Ok?
OpenStudy (anonymous):
0 is not the only solution
OpenStudy (anonymous):
Really?
OpenStudy (anonymous):
sin(180º)=0...right? sin(360º)=0, sin(-180º)=0
OpenStudy (anonymous):
Okk then ?
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OpenStudy (anonymous):
you have to account for every angle
OpenStudy (anonymous):
what is 120 degrees k mean ?
OpenStudy (anonymous):
what is "k" anyway ?
OpenStudy (anonymous):
k is an integer, any integer
OpenStudy (anonymous):
which is how you account for every possible angle theta can be
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OpenStudy (anonymous):
how did they get 120 degrees k then ?
OpenStudy (anonymous):
the answer to this is theta=k*60º, where k is any integer
OpenStudy (anonymous):
for example
k=1 sin(3*60)=sin(180)=0
k=0 sin(3*0)=sin(0)=0
k=-1 sin(3*-60)=0
k=2 sin(3*2*60)=sin(360)=0
OpenStudy (anonymous):
ohh
OpenStudy (anonymous):
where did you get the 60 from?
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OpenStudy (anonymous):
well you could also write 0+k*60º, since we established that the reference angle was 0, but the 0 is unnecessary
OpenStudy (anonymous):
so k= either 0,1,2,3 ?
OpenStudy (anonymous):
k is ANY integer
OpenStudy (anonymous):
the equation will be true whatever the value you plug in for k is
OpenStudy (anonymous):
i see
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OpenStudy (anonymous):
suppose k=500
type in your calculator sin(3*500*60º)
you end up with 0
OpenStudy (anonymous):
ahh ok
OpenStudy (anonymous):
Sin and cos have periodic of 2 pi
=> sin 3Ө = sin 0 + k 2pi
=> 3Ө = 0 + k 2pi
=> Ө = k 2pi / 3 = k 60 degree
k = 1, Ө = 60
k = 2, Ө = 120
...
so on