Question

m

Answer 1

I attempted to solve this triangle several times using Law of Cos.... But I get a Domain Error.

Answer 2

by cosine theorem,
31^2 =17^2 + 22^2 -2(17)(22) cos abc
by calculation, we can get abc

Answer 3

I meant the seperate angles - m<A, m<B, m<C

Answer 4

Also @CoCoTsoi Thats the same equation I set up, with cos B as my unknown. Thats where I ran into problems

Answer 5

I subtracted 17^2 + 22^2 from 31^2. That gave me -138915.
Then I divided by -2(17)(22).

I tried to take the inverse of this fraction, but my calculator informed of a domain error......

Answer 6

31^2 =17^2 + 22^2 -2(17)(22) cos abc
cos abc = (31^2 -17^2 -22^2)/(-2)(17)(22)
cosB = -0.25133
B=105
17/sin C = 31/sinB
C=32

A=180-B-C=43

Answer 7

You are welcome