Question

Determine the quadratic equation for the parabola:
range: {y:y ≤ 9}; x-intercepts: -2 and 4

Answer 1

x = -2
x = 4

(x+2)(x-4) = 0
Solve.

Answer 2

i have to chose from these f(x) = x2 - 2x + 8 f(x) = x2 + 2x - 8
f(x) = -x2 + 2x + 8 f(x) = -x2 - 2x + 8

Answer 3

You may solve this using FOIL and you will get the answer,

(x+2)(x-4) = 0

Answer 4

thankyou

Answer 5

@saifoo.khan (x+2)(x-4) = 0 is not a quadratic equation for a parabola...

Answer 6

it will only give you the x intercepts of the parabola

Answer 7

@anonymoustwo44 , how?
i never said (x+2)(x-4) = 0 is the equation. i him to solve it.


(x+2)(x-4) = 0
x^2 -2x - 8 = 0

This will be it.

Answer 8

x^2 -2x - 8 = 0 is not the answer. its y=x^2-2x-8

Answer 9

It's the same thing.. Just the way of representation is different.

Answer 10

then try to graph an x^2-2x-8=0

Answer 11

But still, the answer you gave to the asker was still wrong.

Answer 12

and so are you

Answer 13

Mine was better than yours. hehe.

Answer 14

Atleast mine dosnt have sign mistakes.

Answer 15

but the fact that you set it to zero

Answer 16

anyways

Answer 17

It's the same thing man.
Just the different way of representation.

Answer 18

It will give us the same answer.

Answer 19

ok sorry if I've been a bit harsh :D

Answer 20

Me too! :D