f(x)=2x+5; g(x)=9x-7
(1.)(f-g)(x)=?

(2.)what is the domain of f-g?
a.{x|x0}(or equal to) b. {x|x-5/2

c. {x|x is any real number} d. {x|x= -5/2}(not equal to)

3.what is the domain of f/g?
a.{x|x=7/9}(not equal to sign) b.{x|x7/9}

c.{x|x0)(or equal to) d.{x|x is any real number}

Question

f(x)=2x+5; g(x)=9x-7
(1.)(f-g)(x)=? 

(2.)what is the domain of f-g? 
   a.{x|x>0}(>or equal to)   b. {x|x>-5/2   

c. {x|x is any real number}   d. {x|x=  -5/2}(not equal to)

3.what is the domain of f/g?
     a.{x|x=7/9}(not equal to sign)  b.{x|x>7/9}
     
     c.{x|x>0)(>or equal to)   d.{x|x is any real number}

anonymous · Answer

Do you mean (f(x)-g(x))*x?

anonymous · Answer

If so, you get: (-7x+12)*X=-7x^2+12x

anonymous · Answer

the top is the question and then you have to answer the bottom 3

anonymous · Answer

I see, what you want to do is use f-g as a reference for the domains etc. f-g=12-7x

anonymous · Answer

As for (2.) I'm fairly sure the answer is c. ($$x \in \mathbb{R}$$

anonymous · Answer

f/g = (2x+5)/(9x-7)
Here you're more limited as 9x-7 cant be 0, unless you want a great explosion from dividing by zero! :D

anonymous · Answer

9x-7=0
9x=7
x=7/9 Therefore x can't be 7/9. The answer would be A.

anonymous · Answer

awesome thank you soo much!!

anonymous · Answer

No problem! Just make sure you understand my reasoning - if you don't, ask!