The closest distance of approach of an alpha particle travelling with a velocity V toward a stationary nucleus is d.For the closest distance to be d/3 towards a stationary nucleus of double the charge the velocity of projection of the alpha particle has to be?

Question

anonymous · Answer

Can you explain what the question meant.I did not get it at all

experimentx · Answer

|dw:1333570275508:dw|

anonymous · Answer

After that repulsion?

experimentx · Answer

since both particles are positively charges, alpha particle will deaccelerate  ... but it will reach a certain point. that is distance d

experimentx · Answer

now if velocity of the alpha particle is increased then this distance will decrease ..

experimentx · Answer

and also charge is increased by twice.

anonymous · Answer

So what I need to find here is the potential at distance d away from nucleus causing all kinetic energy to change into potential energy which I can get from the potential

experimentx · Answer

yep .. exactly.

experimentx · Answer

most likely the problem is going towards ratio.

anonymous · Answer

And should I take nucleus has charge Q

experimentx · Answer

yes ,,,, i doesn't matter what you take.

anonymous · Answer

Oh.Yeah I understand now