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15x-10y=5 15y=-4+5x solve by substitution method with a solution set
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ok, so rearrange one of the equations to solve for x or y
y=1/15(5x-4)
now, sub that into the other equation (for y)
15x-10(1/15(5x-4)=5 this is where iam having problems :(
what, coud you draw that out or use the equation editor?
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i meant to say wait...no difference?
\[15x-10(1/15(5x-4)=5\]
well, you know bedmas right? do it so in such steps
|dw:1333587182418:dw| the thing i get confused when using fractions
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