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What is the laplace transform of e^x
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Isn't it just 1/(s-1) one because 1 is the number in front of x.
It could be - but is there any particular reason it's s-1 instead of s+1
It is always s - the number in front of x. For example, if you wanted the laplace transform of e^-3x, then it would be 1/(s--3), which is 1/(s+3), then it would be positive.
Oh I see well that makes sense - it just seems too simple haha - thank you very much
Sure thing
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