the third term of an arithmetic sequence is 14, and the ninth term is -1. Find the first four terms
ahh tricky problem.. first solve what you are given.. assume that 14 is A1 so An = A1 + (n-1)d A1 = 14 An = -1 n = ? you wanna know d... but...what is n? how many numbers are in the series from the 3rd term to the 9th term?
i dont know, thats my problem too. that was just the problem said on the paper
hahaha =))) let's count... 3rd term 4th term 5th term 6th term 7th term 8th term 9th term how many terms do you see?
oh, LOL. 7
yes! so n = 7...solve for the common difference...show me :D
wait, so is it okay to put a3 in the equation in the a1 spot?
we will assume..there are two equations here...we will first solve for the d and assume that A1 = 14 so...A7 = -1 n =7
ohh okay. thank you!
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