Question

Who wants to help on parabolas? x^2 + 3y = 0
Graph how?

Answer 1

Hint make an (x,y) table

Start with (x,y) = (0,0)

Answer 2

To get the next point, substitute x = 1 into the equation and solve for y:

x^2 + 3y = 0
(1)^2 + 3y = 0
1 + 3y = 0
3y = -1
y = -1/3

So the next point is (1, -1/3)

Answer 3

Keep going until you have enough points to plot an appropriate graph

Answer 4

Solving for y will allow you to plot what the graph looks like on a calculator:

x^2 + 3y = 0
3y = -x^2
y = -x^2/3

Answer 5

If you don't have a graphing calculator, you can use geogebra, use Hero's last equation on the input line.

http://www.geogebra.org/cms/

Answer 6

I've attached what the graph looks like. You should be able to do the rest.

Answer 7

THANK YOU ! !