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Use the quadratic formula to find the roots of the equation. x2 + 3x - 18 = 0 A.{-6, 3} B.{-2, 9} C.{-3, 6} D.{-9, 2}
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quadratic formula is \[x=(-b \pm \sqrt{b^2-4ac})/(2a)\] Put a=1, b=3 and c=-18 to the formula and see what you can get :)
A. http://www.wolframalpha.com/input/?i=solve+x2+%2B+3+x+-+18+%3D+0+&t=sftb01
\[x=(-3 \pm \sqrt{3^2-4(1)(-18)})/(2(2))\]
thank you :)
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