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Factor completely: 9x^2 + 42x + 49
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Use the (a + b)^2 identity. (3x)^2 + 2(3x)(7) + 7^2 =(3x + 7)^2
(3x+7)(3x+7)
(3x + 7)(3x + 7) (3x + 7)(3x - 7) (9x - 7)(9x - 7) (9x + 7)(9x + 7)
First option.
(3x-7)^2
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\[\frac{\left( 9x+21 \right)\left( 9x+21 \right)}{9}=\left( 3x+7 \right)^{2}\]
And Tributized, you made a mistake.
i know :(
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