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cos2x=cos^2x-1/2
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\[\frac12(1+\cos(2x))=\cos^2x\]
Wow, Turing!! how do you derive that? :P
I would like to know as well
\[\cos \left( 2x \right)=\cos \left( x+x \right)=\cos ^{2}x-\sin ^{2}x=2\cos ^{2}x-1\]\[2\cos^{2}x - 1 =\cos \left( 2x \right)\]\[\cos^{2}x=\frac{1}{2}\left( 1+\cos \left( 2x \right) \right)\]
Whats the exact angle for this?
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sorry for not deriving that earlier I use that formula so often for integration I forget it's not so commonly known in precalc thanks @extraven for filling in the missing proof!
^ @exraven I meant. oops :/
you are welcome :)
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