Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

cos2x=cos^2x-1/2

OpenStudy (turingtest):

\[\frac12(1+\cos(2x))=\cos^2x\]

OpenStudy (anonymous):

Wow, Turing!! how do you derive that? :P

OpenStudy (anonymous):

I would like to know as well

OpenStudy (anonymous):

\[\cos \left( 2x \right)=\cos \left( x+x \right)=\cos ^{2}x-\sin ^{2}x=2\cos ^{2}x-1\]\[2\cos^{2}x - 1 =\cos \left( 2x \right)\]\[\cos^{2}x=\frac{1}{2}\left( 1+\cos \left( 2x \right) \right)\]

OpenStudy (anonymous):

Whats the exact angle for this?

OpenStudy (turingtest):

sorry for not deriving that earlier I use that formula so often for integration I forget it's not so commonly known in precalc thanks @extraven for filling in the missing proof!

OpenStudy (turingtest):

^ @exraven I meant. oops :/

OpenStudy (anonymous):

you are welcome :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!