Question

Use the square root property to solve the equation:
3x^2-39=0

Answer 1

3x^2 = 39
x^2 = 13
x = SQRT(13)

Answer 2

\[\LARGE 3x^2-39=0\]

\[\LARGE 3x^2=39\]

\[\LARGE x^2=\frac{39}{3}\]

\[\LARGE x^2=3\]

\[\LARGE x=\pm\sqrt{3}\]

Answer 3

how would i type that as a solution set?

Answer 4

\[3x ^{2}-39=0\]
\[3x ^{2}=39\]
\[x ^{2}=13\]
x=\[\sqrt{13} or x= \sqrt[-]{13}\]
now what do i do?

Answer 5

use \pm for \[\LARGE \pm\]

Answer 6

no im saying how do i type that as an ordered pair, is it \[(\sqrt{13},-\sqrt{13}) ??\]

Answer 7

\[\LARGE x\in \{\sqrt{3},-\sqrt{3}\}\]

\LARGE x\in \{ \sqrt{3} , -\sqrt{3} \}

this is how you type in Equation button !

Answer 8

sorry... I made a mistake in my TWO postst replace \sqrt{13} instead of \sqrt{3}

Answer 9

ok thanks

Answer 10

you're welcome :)