Question

@callisto, can you help me?

Answer 1

Yes? I'm not sure if I can, but i'll try :)

Answer 2

I'm so confused...What is your question?

Answer 3

For this question, put it in Physics group next time
s= ut + 1/2 (gt^2)
= 0 +1/2 (10 x10^2)
= 500
Height = 3125 -500 =2625

Answer 4

Last term = a + (n-1)d = 5 + (12-1)(-3) = -28
Sum = (a+l)d /2 = [5+(-28)]*12/2 = -138

Answer 5

What is the first term?

Answer 6

You have the general term
t(n) = 2n-1
Put n=1 you'll get the first term, can you try?

Answer 7

Yes, what's the first term then?

Answer 8

(2*1)-1 :S

Answer 9

What is the 100th term(last term of the sum) then?

Answer 10

To find the 100th term, put n=100 into t(n) = 2n-1...

Answer 11

not yet, you're on the half way to the answer

Answer 12

yes,
Sum of AS = [(first term)+last term] * number of terms /2
Can you do it now?

Answer 13

that's the answer

Answer 14

Nah, perhaps you should open new post for each question?!

Answer 15

t(n) = ar^(n-1)
1/84 = 1/84 (2)^(3-1)= 4/84

Answer 16

medal is not my concern in this case, sorry

Answer 17

s = 0 + 1/2(10)(10)^2 - 0 + 1/2(10)(9)^2 =95

Answer 18

= 0 + 1/2(10)(10)^2 -( 0 + 1/2(10)(9)^2) =95

Answer 19

I type you the answer just because you're in a hurry... now, you need to learn :S

Answer 20

Nah.. not that serious...

Answer 21

Nope you don't need to, it's alright but next time, post it separately

Answer 22

Nope, don't want it to be a 'medal party' in mods' eyes

Answer 23

Now, it's the learning time!

Answer 24

t(n) = ar^(n-1)
Put a=1/84, r=2, n=1 into the formula and you'll get the answer

Answer 25

sorry, it was n=3 in your question :S

Answer 26

yes, which is?

Answer 27

1/84*2^(3-1) = 2^2 /84 = 4/84 = 1/21

Answer 28

Welcome.... i'm not good enough to be a mod though... not even an ambassador !

Answer 29

and you know, mods and ambassadors here great :)

Answer 30

Don't say that!

Answer 31

Glad that I can help :) But your teacher teaches you the basic, which makes me easier to explain :D

Answer 32

Once again , welcome! Have a nice day :)