ahh @FoolForMath pretty sure this is a hard one this time >:)))) Four members of a band are walking to a night concert. They decide to take a shortcut, but must cross a bridge. Luckily they have one flashlight. Because of the varying size of their instruments, it takes each member a different amount of time to cross the bridge - it takes the first person one minute, the second person two minutes, the third person five minutes and the fourth person ten minutes. They must cross the bridge in pairs, traveling at the slower speed so if the one minute person went with the ten minute person, it w
it would take a total of ten minutes. Since there is only one flashlight, one person must come back across the bridge, then another pair can cross. They only have 17 minutes to cross the bridge and still get to the concert on time. What order should they cross to get everyone across and get to the concert?
the fastest person holds the light slowest and fastest first, , slowest wait on the other side , the fastest comes back to pick up the next slowest,...
No... it takes 19 mins... 10+1+5+1+2 = 19 ...
wrong @UnkleRhaukus :P hehehe
i hope there is a solution....:)
wrong?
or should they just ditch the slow guy and play as a tri
lol =)))0
why do you need a light to cross a bridge, why can you only travel in pairs this is absurd 10+1 5+1 2 = 19
trio*
1 +2 go -> 2 1 back -> 1 5+10 go ->10 2 back -> 2 1+2 go -> 2 ------------->17 right?
ok good answer, group the slow guys together
@Callisto is right! yay! :DDD
Unfortunately this question is for FFM... :S
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