Question

how to do expansion and factorization of algerbraic epressions
?

Answer 1

@alliyah visit this website http://www.haesemathematics.com.au/samples/ibmyp2_10.pdf

Answer 2

can u explain that to me like how would u exspand the question and stuff

Answer 3

expansion\[a(b+c)=ab+bc\]\[(d+e)(f+g)=df+dg+ef+eg\]

Answer 4

is this what you mean?

Answer 5

yes plsss help me with it

Answer 6

\[ax+bx+cx^3=x(a+b+cx^2)\]

Answer 7

It might help to have a specific question
do you have any or do you want me to make one up

Answer 8

yes

Answer 9

simplify by factorizing\[2a+4ab+32a^2b\]

Answer 10

ok first give me a expansion question and walk me thru the steps plsssss

Answer 11

expand\[(4+z)(21az)\]

Answer 12

so this is the same as \[(4 \times 21az) +(z\times21az)\]

Answer 13

ok so how did u get 2 z

Answer 14

?

Answer 15

oh dear ,
what have i done.
how embarrassing
i dont know how that happened @Kreshnik
....

Answer 16

yall confusing me plp

Answer 17

@UnkleRhaukus It's ok, It happens, we're not robots , I KNOW THAT YOU KNOW IT you just made a typing mistake, but the asker could misunderstand and learn it wrong...

I just want to clarify it ;) Go ahead explain him how it is... Sorry for interrupting ;)

Answer 18

i was working through the alphabet and i got to ...h,i, but i dident think it was a good idea to use i ( as it could be read as the imaginary number) which would have been confusing . and i guess that became my focus i forgot to check for errors ....
Thank for pointing it out, im glad to have deleted it .

Answer 19

yall tryna make me fail twice now comn help me out plsssssss one person at a time

Answer 20

It is had without a specific question to answer alliyah1998

Answer 21

\[\LARGE (a-b)(a+b)=a^2-b^2\]

because ...

\[\LARGE a\cdot a +a\cdot b- b\cdot a -b\cdot b= a^2-b^2 \]

because -ab and +ab =0 so they cancel out !

Answer 22

ok then explain how i do (4+z) (21az)

Answer 23

@alliyah1998 if there's something you don't understand we can give you a hint, but if you don't know the most of the rules, is worthless for us to try to teach you. You better go and ask your teacher !

Answer 24

just explain how u would expnad the problem i put up thats all im messing

Answer 25

do each bit in the sum one at a time
(4+z) times 21az
becomes
4 times 21az + z times 21az

Answer 26

\[(4+z) (21az)=4\times21az+z+21az\] am i right?

Answer 27

if your second plus on the right hand side is meant to be a times
yes

Answer 28

ok oh yeh yeh my fault ok giv me a nother problem

Answer 29

first u do 4*21az then u +z then u do *21az am i correct

Answer 30

....hence
\[(4+z)(21az)=84az+21az^2\]

Answer 31

so 4**21az+z*21az=84az+21az2 because u have two az so u have to squa

Answer 32

please do not write "you" as u or 'to' as 2
very confusing

yes \[ z \times z= z^2\]

Answer 33

ok sorry can you give me another problem

Answer 34

\[\LARGE (x^2\cdot z^3)\cdot (5x\cdot z^{-4})\]

@alliyah1998 try this

Answer 35

ok waht i have so far is \[x ^{2} \times5x+z ^{3} \] what do you do with the negitive 4?

Answer 36

@alliyah1998

do you know where is the difference between...
\[\LARGE (x^2\cdot y^3)\cdot (x^7\cdot y^2)\]
and ..
\[\LARGE (x^2+ y^3)\cdot (x^7+ y^2)\]

Answer 37

your multiplying in one question and your addin in the other

Answer 38

can you solve them for me ?

Answer 39

im tryna solve the first one u gave me help me with that one first then we can go onto new ones ok

Answer 40

hint...

1. I'm not giving math lessons here !

2. Go ask your teacher, he'll explain them to you ! ;)

3. Have a nice day.