Question

32 + (8 - 2) • 4 - 6/3

Answer 1

its not 32, its 3 squared

Answer 2

your answer is 31 . we'll first solve the bracket

Answer 3

hint..
\[\Large 32+(8-2)\cdot 4 -6\sqrt3=32+6\cdot 4-6\sqrt3\]

Answer 4

apply BODMAS i.e Bracket Of Division Mulitiplication Addition Substraction... z answer is 25

Answer 5

@nataliaviruet you said number three is under square root didn't you ?

Answer 6

ahh ok its 9 not 32 zen \[9+\subset6\supset \times4-2\] zen simplify to get 31

Answer 7

I guess I got it wrong. O_O didn't I ?

Answer 8

lol its 31

Answer 9

@nataliaviruet you said:

nataliaviruet This is the asker
its not 32, its 3 squared

I see it like:
32 + (8 - 2) • 4 - 6/3

and I thought it must be :

\[\Large 32+(8-2)\cdot 4-\frac63\]

but then according to you I put number three under square root and wrote it like:

\[\Large 32+(8-2)\cdot 4-6\sqrt3\]

but now I guess 32 isn't right or what ??