Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, -1).

Question

hoblos · Answer

thats almost the same as the previous!! can you try to solve it?

anonymous · Answer

alright ill try my best lol

hoblos · Answer

tell us what you get so that we can check it ;)

karatechopper · Answer

parallel= same slope
perpendicular= opposite of reciprocal  Ex. slope= 1/4     perpendicular slope: -4/1

anonymous · Answer

ok so far i got it in slop int form : y=-3x+7 
is that right?

karatechopper · Answer

yes

anonymous · Answer

i ended up with y = -3x - 3
correct?

anonymous · Answer

I see but wouldnt it be y = -3x + 17 ?

hoblos · Answer

let the line we want equation of be (d) and its slope is m
slope of y=-3x+7 is m' = -3

m*m'=-1
so m = 1/3

y+1 = (1/3)(x-6)
y+1 = (1/3)x -2
  y = (1/3)x -1