Question

Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, -1).

Answer 1

thats almost the same as the previous!! can you try to solve it?

Answer 2

alright ill try my best lol

Answer 3

tell us what you get so that we can check it ;)

Answer 4

parallel= same slope
perpendicular= opposite of reciprocal Ex. slope= 1/4 perpendicular slope: -4/1

Answer 5

ok so far i got it in slop int form : y=-3x+7
is that right?

Answer 6

yes

Answer 7

i ended up with y = -3x - 3
correct?

Answer 8

I see but wouldnt it be y = -3x + 17 ?

Answer 9

let the line we want equation of be (d) and its slope is m
slope of y=-3x+7 is m' = -3

m*m'=-1
so m = 1/3

y+1 = (1/3)(x-6)
y+1 = (1/3)x -2
y = (1/3)x -1