2 square root of 7x + square root of 7x - 3 square root of 7x - 7
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OpenStudy (anonymous):
is it ...
\[\LARGE 2\sqrt{7x}+\sqrt{7x}-3 +\sqrt{7x}-7\]
or
\[\LARGE 2\sqrt{7x}+\sqrt{7x-3} +\sqrt{7x-7}\] ?
OpenStudy (anonymous):
yes to the first one
OpenStudy (anonymous):
then I think this should help...
\[\Large a\sqrt{7x}+b\sqrt{7x}=(a+b)\sqrt{7x}\]
OpenStudy (anonymous):
thank you
OpenStudy (anonymous):
do you know how to do it now ?
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OpenStudy (anonymous):
i am trying to figure it out right now
OpenStudy (anonymous):
If you can't just let me know... I'll help you ;)
OpenStudy (anonymous):
thank you so much
OpenStudy (anonymous):
you're welcome ;)
OpenStudy (anonymous):
is the answer 3 square root of 7x - 7
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OpenStudy (anonymous):
?
OpenStudy (anonymous):
\[\Large 2\sqrt{7x}+\sqrt{7x}-3+\sqrt{7x}-7=\]
\[\Large 2\sqrt{7x}+\sqrt{7x}+\sqrt{7x}-7-3=\]
\[\Large (2+1+1)\sqrt{7x}-7-3=\]
\[\Large 4\sqrt{7x}-10\]
@cassandre if you're still confused about steps I made solving it , feel free to ask ;)
OpenStudy (anonymous):
omg, i see where the issue is, i forgot to combine the -7 with the - 3