Question

i have never learned squeeze theorem, someone help me out here pls


limit x to 0 of 2x^2 sin (2/x^3)

Answer 1

I know you haven't learned squeeze theorem, but with it the problem becomes much easier. The limit would be 0 because you would take the limit of -2x^2 and 2x^2 as x=>0 ending in 0

Answer 2

oh ok