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what are the rules for these two (f of g)'(4) (f^-1 of g) (6)
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f'(g)g'(4) f^-1(g(6))
i dont understand
first one is the derivative of combined function. Just asks for chain rule second is combined function...
dpalnc your drawing doesnt show properly on the screen
sorry
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its ok. you mind just writting out the formula?
as @myko, says, it's just the chain rule...
ok
f^-1 g(6) if you were using a table...you would find g(6) right? lets assume g of 6 =5 to find f^-1, do you look what which x value give an f value of 5?
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