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Show how to solve (for blondes): 2 sin x + sqrt(3) = 0. Answers are 4pi/3 and 5pi/3.
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2 sin x + sqrt(3) = 0 2sinx = - sqrt(3) sinx = - sqrt(3) /2 For sinx = sqrt(3) /2 x = 60 degree = pi /3 Since it has a negative value, the angle is in quadrant III or quadrant IV Therefore, x = pi + pi /3 = 4pi /3 and x = 2pi - pi /3 = 5pi /3
\[ \sin(x) = -\frac {\sqrt 3} 2= \sin(-\pi/3) \]
\[ x = -\pi/3 + 2 k \pi \] or \[ x = \pi -(-\pi/3) + 2 k \pi = 5 \pi/3 +2 k \pi\]
\[ k = \pm 1, \pm 2, \pm 3, \cdots , \]
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