A battery can operate 8 toys for 21 hours. For how long could the battery operate 15 bears?
I was hope you would answer
I have been messing arounf with it and I do have an answer
i done 8*21=15x where x is the hours
@Hollywood_chrissy I was doing in the same way as you :S
:) but I dont stand what I done.
A battery can operate 8 toys for 21 hours so for 1 toy =21/8 hours 15 toys =21/8 * 15 ?
Less toys more time so it's inversely proportional. Using unitary method: 8 toys for 21 hours 1 toys for 21*8 hours 15 toys in \( (21\times8)/15 = \frac{56}{5} = 11.2 \) hours
Isn't 1 toy 21/8 hrs?
If we use batteries of 8 toys in just 1 toy then the battery will last long. So more time.
OOOOh okay!!
NO worries diya, I got deceived too :P
Here comes the question...Is it 8 toys for 21 hours each (total time = 8x12 hours )or 21 hours for 8 toys ... That's what I'm thinking of.... :S (personally i think it is the first case)
This question is somehow like the previous one you asked..
@Hollywood_chrissy: Do you know the right answer? :)
Hollywood_chrissy and FoolForMath both have the correct answer. Increasing the number of toys will drain the single battery faster.
can I get an good answer????
Assume you've got the correct numerical answer. Here is the explanation. The total operating hours for the battery = 8x21 = 168 hours, understand this part?
yes
Now, you have the same battery, that means the total operating hours for the battery remains unchanged, that is 168 hours. understand this part?
yes
Then, you have 15 bears now. You want to use the battery to operate these 15 toys (equally), understand this part?
yes
So let x be the number of operating hours per bear. number of bear * number of operating hours per bear = total number of working hours 15 x = 168 Understand this part?
yes
solve x and you'll get the answer you want. By the way, is the answer correct?
yes 11.2 hours
Good :) Do you understand it now?
I do
thank you once more.
Glad to hear :) and you're welcome :)
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