There are 6 different presents and 5 children. How many ways can at least 1 present be given to each child?
6C5*5!+6C5*5!*5 ... perhaps
Not permutations?
@mridrik Do you know about Stirling number of second kind?
I did 6 different for first person x 5 diff for next x 4 x 3 x 2, then the last present has 5 different people to go to so times 5 again?
no i do not know what that is
Okay, undergrad student I suppose?
8th grade
Oh lol. Where do you get this problem from?
state mathcounts test. Is my answer right? 3600?
what is stirling number of second kind?
I am getting 1800.
Where is satellite?
How did you get 1800?
n distinct object into r distinct groups at-least one in each group is consistent to counting the surjection from a set of n elements to a set of r elements. But this is probably a bit hard for you to understand. There might be a pedestrian way of doing this which I can't think of now.
looks my answer was 4320 ... i might have misunderstood the question. since i am always prone to.
at first i got that
why doesnt the way i did it work?
so ... whats does the question exactly say, 6 presents or 6 different types of present??
I really wish if I am reading something wrong :( It's a bit harder for a 8th grader.
it is i believe ... i never could do those even in my undergrad.
There must be a pedestrian way of doing this. I am fairly confident about my answer.
@myinaya: Am I missing something?
@myininaya
6 different presents, 6 total presents
let's draw a diagram|dw:1333927226126:dw|
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