Question

how do i find the eigenvector?

Answer 1

\[\left( A-\lambda I \right)x=0\]lamda is the eigenvalue, x is the eigenvector

Answer 2

i was able to find the eigenvalue \[\left[\begin{matrix}-6 & 1 \\ -2 & -3\end{matrix}\right]\]
to be \[\lambda _{1}=-4, \lambda _{2}=-5\]
now what's the next step?

Answer 3

@nightshade please don't post off-topic answers.
@exraven and elica85 we want x to not be the zero vector also

Answer 4

Did you try to plug into exraven's formula to find the eigenvectors

Answer 5

i thought it's lambdaI-A, not A-lambdaI

Answer 6

idk what i'm doing, my school doesn't require us to take linear algebra to take diff eq so i'm suppose to know what to do but i don't

Answer 7

o if i just have to find x, i should be able to...

Answer 8

\[(A-\lambda_n \cdot I)x=0\]
For \[\lambda_1=-4\]