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there are 5 blue pencils and 3 gold pencils in a container. if 2 pencils are drawn at random without replacement, what is the probability that both pencils drawn are gold? express your answer as a fraction in simplest form.
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\[\frac{3}{8}\times \frac{2}{7}\]
without replacement tells you the draws are independent that allows you to use P(A and B) = P(A)P(B) where A is the probability that the first draw is a gold pencil and B the prob. that the second draw is a gold pencil
actually without replacement tells you the draws are DEPENDENT
so it is \(P(A\cap B)=P(A|B)P(B)\)
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