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solve the equation for 0
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Now substitute the value of cos45=1/sqrt(2)
how did you get to that?
sorry, im still confused
oh! so it comes to be 2cosx (root2/2)=root2
The value of cos45 is a standard value. You should know it. \[2cosxcos45=2cosx(1/\sqrt{2})=\sqrt{2}cosx\] Now proceed
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ohh. so it ends up being cosx=root2/root2 so cosx=1?
Yes. Now, do you know how to find the values for x?
0 and 360 degrees?
Yes. The general solution of cosx=1 is x=2nPI
thank you!
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