Question

Does sqrt{x+1} = (x+1)_{2}^{1}

Answer 1

\[Does \sqrt{x+1} = (x+1)_{2}^{1}\]

Answer 2

Yes.

Answer 3

\[\sqrt{x+1} = (x+1)^{\frac12}\]

Answer 4

So does

\[( (x+1)_{2}^{1})_{}^{2} = (x + 1)_{2}^{2} = x + 1 ???\]

Answer 5

Yes.

Answer 6

Can

\[(\sqrt{4x+7})_{}^{2} = (\sqrt{4x + 7})(\sqrt{4x + 7}) ??\]

Answer 7

Correct.

Answer 8

But wouldn't multiplying those give a trinomial answer?

Answer 9

No

Answer 10

\[\sqrt{3} \times \sqrt{3} = 3\]

Answer 11

There must be a rule I am missing, can only the 4x * the 4x and the 7 * the 7 Inside the radicals?

Answer 12

Sorry, rephrase please?

Answer 13

Ill make new question

Answer 14

Perfect.