How do I apply Heron's formula for a triangle? Let's suppose I have a triangle as follows, and I want to find Cos B ... how would it be?
draw a perpendicular from C on AB
ok .. let's suppose I did it. Now ... :) ?
partition is as x and c-x ,, for c
and put y for that vetical dist
... can you make a sketch please, I can't do it , O_O. too confused !
That's not heron's formula...
That's the law of cosines.
Hmmm... I think that's cosine law in your diagram... Heron's formula is used to find the area of triangle :S
ok whatever, tell me how do I find cos B if I have all sides given ? :(
Heron's formula gives the area of a triangle given three side lengths
Put the values into the formula :S
Plug in the values, then take the arccosine
or cos^(-1)
Should be on your calculator.
i was thinking the same ... thought i couldn't remember the exact proof. except vector dot product.
... ok hold on a second I have something.. to show !
Give the three side lengths, and we'll walk you through. NOte that this is the law of cosines.
... ok , I had this problem time ago , and I did it. (at least I thought I did it.) the area I got was 72. but tell me formulas which are to find area of this triangle ans Cos B
for triangle ABC
tell me angle, and for all triangle how do you find area , if you don't mind :(
okay ... i figured it out.
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