factor x^(2)-3x+5
Hint: Find two numbers that multiply to get 5, but add to get 3. 2nd Hint: If you fail to find the two numbers, the polynomial might be prime.
use quadratic formula
i know how to do it but the factors of 5 are 5 and 1 which n no way add to 3
Well, see if you can make them equal -3. If not, then the polynomial could be prime.
problem is im trying to find the x intercepts of a parabola... problem is \[y=-x ^{2}+3x-5\]
Well, in that case, set y = 0, then complete the square.
did that... \[0=-x ^{2}+3x-5\] multiply by -1 \[0=x ^{2}-3x+5\] then factor to find x intercepts
Ask yourself this question: Does an x-intercept exist?
D = b^2 - 4ac If the discriminant is negative, then no, there doesn't exist an x-intercept.
its a parabola... should have 2 x intercepts, a y intercept, a vertex, and a 5th point. its a big U shaped graph
It "should" , but there exists many parabolas that fail to intercept the x-axis. Trust me.
ok thanks
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